One letter must end 'pea' and begin 'ot' — R makes pear and rot. And when two letters both seem to work, the second bracketed pair settles it. Systematic candidates beat inspired guessing.
pea_: pear, peak, peal, peas — list the real candidates.
_ot: rot ✓ (r), kot ✕, lot ✓ (l), sot ✕… wait — both r and l work? Check: peaL ✓ Lot ✓ too!
Papers give TWO bracketed pairs needing the SAME letter: sta( )ice → staR/Rice fixes R.
Find the one letter for both pairs: hea ( ? ) all and sof ( ? ) able
Both words! The letter must finish the left AND start the right.
The tiebreak! When R and L both fit pair one, only the letter that also completes pair two is correct.
Dictionary check! ‘Pall’ is actually a word — but does it fit pair two? sofP ✕. Rare words can fit one pair; the SECOND pair still decides.
A single letter sits in the bracket, finishing the word before it and starting the word after: pea(R)ot gives pear and rot.
Use the question's second pair — the same letter must complete both pairs, which almost always leaves exactly one option.
Generate candidates from the left word systematically (run through the alphabet), then filter — it's faster and safer than hoping the answer pops out.
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